8x^2-8=328

Solution for 8x^2-8=328 equation:

8x^2-8=328

We move all terms to the left:

8x^2-8-(328)=0

We add all the numbers together, and all the variables

8x^2-336=0

a = 8; b = 0; c = -336;
Δ = b2-4ac
Δ = 02-4·8·(-336)
Δ = 10752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10752}=\sqrt{256*42}=\sqrt{256}*\sqrt{42}=16\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{42}}{2*8}=\frac{0-16\sqrt{42}}{16}
=-\frac{16\sqrt{42}}{16}
=-\sqrt{42}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{42}}{2*8}=\frac{0+16\sqrt{42}}{16}
=\frac{16\sqrt{42}}{16}
=\sqrt{42}
$